Find Minimum in Rotated Sorted Array — Binary Search O(log n) [Google, Microsoft]
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Problem Statement
Given a sorted rotated array with unique elements, find the minimum.
Input: [3,4,5,1,2] → 1 Input: [4,5,6,7,0,1,2] → 0
Intuition
If nums[mid] > nums[right], the minimum is in the right half. Otherwise it's in the left half (including mid).
C++ Solution
class Solution {
public:
int findMin(vector<int>& nums) {
int l=0, r=(int)nums.size()-1;
while (l<r) {
int mid=l+(r-l)/2;
if (nums[mid]>nums[r]) l=mid+1;
else r=mid;
}
return nums[l];
}
};
Java / Python / JavaScript Solution
def findMin(nums):
l, r = 0, len(nums)-1
while l < r:
mid = (l+r)//2
if nums[mid] > nums[r]: l = mid+1
else: r = mid
return nums[l]
Complexity: O(log n) time, O(1) space
With Duplicates: When nums[mid]==nums[r], can't determine direction → r--. Worst case O(n).
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